Similarly all other intensities cancel out each other and the total electric field at centre is zero. The series combination is connected across a 48-V. Three capacitors are in series: C1 45 muF, C2 65 muF, and C3 80 muF. ![]() ![]() Given,Side of cube=bCharge on vertices of cube =qDiagonal DF of cubeDF = b 2 + b 2 + b 2 DF = b 3Thus, DO = DF 2 = 3 2 bDue to one charge q the potential at the centre O is given byV = 1 4 πε 0 q r = 1 4 πε 0 q 3 b 2Due to eight charges the total potential at the centre O is given as,V = 8 1 4 πε 0 q 3 2 b= 4 q 3 πε 0 bElectric field at the centre of of cube:Due to two opposite corners D and F electric field intensity at the centre ‘O’ are equal in magnitude and opposite in direction. If you are given three identical capacitors of capacitance 1.0 mu f each, how many different capacitance values can you obtain C1 4F, C2 4F, C3 2F, C4 4F, C5 2.5F. Given, C 1,C 2 and C 3 are three identical parallel plate capacitor with capacitances C each.Initially, air is filled in between the parallel plates as the medium.After introducing the dielectrics, the capacitance of capacitors C 1, C 2 and C 3 respectively is given as,Capacitance across first capacitor, C 1 = kε 0 A d Capacitance across second capacitor, C 2 = 2 ε 0 A d k 1 k 2 k 1 + k 2 Capacitance across third capacitor, C 3 = ε 0 A 2 d k 3 + k 4Since, C 1=C 2=C 3 we have,kε 0 A k = 2 ε 0 A d k 1 k 2 k 1 + k 2 = ε 0 A 2 d ( k 3 + k 4 )k = 2 k 1 k 2 k 1 + k 2 = k 3 + k 4 2.
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